x^2+8x-5700=0

Solution for x^2+8x-5700=0 equation:

x^2+8x-5700=0

a = 1; b = 8; c = -5700;
Δ = b2-4ac
Δ = 82-4·1·(-5700)
Δ = 22864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22864}=\sqrt{16*1429}=\sqrt{16}*\sqrt{1429}=4\sqrt{1429}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{1429}}{2*1}=\frac{-8-4\sqrt{1429}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{1429}}{2*1}=\frac{-8+4\sqrt{1429}}{2}
$